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Answer :
Answer:
0.0225 M
Explanation:
In one liter of this solution, there are 45 mEq of Ca⁺².
1 mEq of Ca⁺² is equal to 20 mg of Ca⁺. We know this by dividing its molar mass (40) by the charge of the ion (2).
Meaning that 45 mEq of Ca⁺² is equal to (45 * 20) 900 mg of Ca⁺².
Now we convert 900 mg of Ca⁺² into moles, using its molar mass:
- 900 mg / 1000 = 0.9 g
- 0.9 g Ca⁺² ÷ 40 g/mol = 0.0225 mol Ca⁺²
Finally we calculate the molarity of the solution:
- Molarity = moles / liters
- 0.0225 mol / 1 L = 0.0225 M
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