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Answer :
794.4 in²
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To determine the minimum amount of plastic wrap needed to cover 8 cylindrical containers, we first need to find the surface area of one container.
The surface area (SA) of a cylinder includes the areas of the two circular bases and the rectangular side (label). The formula is:
- Base area: πr² = πd²/4
- Side area: 2πrh = πdh
Where:
- r = radius (or d is diameter) of the base
- h = height of the cylinder
For the given cylinders:
- Diameter = 5.5 inches
- Height (h) = 3 inches
Calculating the total surface area:
- SA = 2*(base area) + side area
- SA = πd²/2 + πdh
- SA = 3.14*5.5(5.5/2 + 3) = 99.3025 in²
For 8 containers:
- Total SA for 8 containers = 8 * 99.3025 = 794.42 in²
Therefore, the minimum amount of plastic wrap needed is 794.4 in² (option D).
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