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Triangle PQR=TSR
PROVED
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Rewritten by : Barada
By using the AA similarity theorem it is proved that triangle QPR is similar to triangle STR.
In the triangle PQR and TSR,
QR is perpendicular to PT.
This implies,
Measure of QRP = 90 degree
Measure of angle QRT = 90 degrees
As Q-S-R
∠QRT = ∠SRT
m∠SRT = 90°
⇒∠QRP ≅ ∠SRT ( as all right angles are congruent to each other)
And its given m∠QPR ≅m∠STR
By applying AA similarity theorem we have,
ΔQPR ~ ΔSTR
Therefore, it is proved that triangle ΔQPR ~ ΔSTR.
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