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Answer :
403.6 grams of sucrose (C12H22O11) are in 1.55L of 0.758M sucrose solution.
HOW TO CALCULATE MASS:
- The mass of a substance can be calculated by multiplying the number of moles by its molar mass.
- However, the number of moles in the sucrose solution needs to be calculated as follows:
- no. of moles = molarity × volume
- no. of moles of sucrose = 0.758 × 1.55
- no. of moles = 1.18 moles
- Molar mass of C12H22O11 = 12(12) + 1(22) + 16(11)
- Molar mass of C12H22O11 = 144 + 22 + 176
- Molar mass of C12H22O11 = 342g/mol
- Mass of sucrose = 342g/mol × 1.18
- Mass of sucrose = 403.6g
- Therefore, 403.6 grams of sucrose (C12H22O11) are in 1.55L of 0.758M sucrose solution.
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Answer : The mass of sucrose are, 402 grams
Solution :
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Formula used :
[tex]M=\frac{w}{M\times V}[/tex]
where,
M = molarity of solution = 0.758 M = 0.758 mole/L
w = mass of solute (sucrose) = ?
M = molar mass of solute (sucrose) = 342 g/mole
V = volume of solution in liter = 1.55 L
Now put all the given values in the above formula, we get the mass of sucrose.
[tex]0.758mole/L=\frac{w}{342g/mole\times 1.55L}[/tex]
[tex]w=402g[/tex]
Therefore, the mass of sucrose are, 402 grams
