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Select the correct answer from each drop-down menu.

1. If a heterozygous male with the genotype Ww is mated with a homozygous recessive female of genotype ww, there is a 50% chance that the offspring will be heterozygous.

2. If a homozygous recessive individual, ww, is crossed with a homozygous dominant individual, WW, then the probability of having a homozygous recessive offspring is 0%.

Answer :

Sure, let's work through the genetics problem step-by-step.

1. First Scenario:
- We have a heterozygous male with the genotype Ww and a homozygous recessive female with the genotype ww.
- To find out the potential genotypes of their offspring, we use a Punnett square to combine the alleles:

```
| | w | w |
|---|---|---|
| W | Ww| Ww|
| w | ww| ww|
```

- From the Punnett square, you can see the possible offspring genotypes are: Ww, Ww, ww, ww.
- This means there are two Ww (heterozygous) and two ww offspring.
- Therefore, the chance of an offspring being heterozygous (Ww) is 2 out of 4, which simplifies to 50%.

2. Second Scenario:
- Here, a heterozygous individual with the genotype Ww is crossed with a homozygous dominant individual with the genotype WW.
- Again, we use a Punnett square to determine the possible genotypes of their offspring:

```
| | W | W |
|---|---|---|
| W | WW| WW|
| w | Ww| Ww|
```

- In this scenario, there are two WW and two Ww genotypes.
- This means there are no offspring with the homozygous recessive genotype (ww).
- So, the probability of having a homozygous recessive offspring is 0%.

By analyzing these steps carefully, you can understand the genetic probabilities in each of the scenarios.

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