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Answer :
Alright! Let's go through the problem step by step to determine the number of protons, neutrons, and electrons for each of the given atoms.
For each atom:
1. Identify the atomic number (number of protons)
2. Identify the mass number (sum of protons and neutrons)
3. Calculate the number of neutrons (mass number - atomic number)
4. Determine the number of electrons, which is equal to the number of protons in a neutral atom
Let's proceed with each element:
### a. Nb-94
- Nb (Niobium) has an atomic number of 41.
- Mass number is 94.
- Protons: 41
- Neutrons: 94 - 41 = 53
- Electrons: 41
### b. [tex]\( \text{Os-191} \)[/tex]
- Os (Osmium) has an atomic number of 76.
- Mass number is 191.
- Protons: 76
- Neutrons: 191 - 76 = 115
- Electrons: 76
### c. Pu-244
- Pu (Plutonium) has an atomic number of 94.
- Mass number is 244.
- Protons: 94
- Neutrons: 244 - 94 = 150
- Electrons: 94
### d. [tex]\( \text{ }_{15}^{31} P \)[/tex]
- P (Phosphorus) has an atomic number of 15.
- Mass number is 31.
- Protons: 15
- Neutrons: 31 - 15 = 16
- Electrons: 15
### e. Xe-132
- Xe (Xenon) has an atomic number of 54.
- Mass number is 132.
- Protons: 54
- Neutrons: 132 - 54 = 78
- Electrons: 54
### f. [tex]\( \text{ }_{83}^{210} Bi \)[/tex]
- Bi (Bismuth) has an atomic number of 83.
- Mass number is 210.
- Protons: 83
- Neutrons: 210 - 83 = 127
- Electrons: 83
### Summary
Here's a quick summary table:
| Element | Protons | Neutrons | Electrons |
|-------------|-------------|--------------|---------------|
| Nb-94 | 41 | 53 | 41 |
| P-31 | 15 | 16 | 15 |
| Os-191 | 76 | 115 | 76 |
| Xe-132 | 54 | 78 | 54 |
| Pu-244 | 94 | 150 | 94 |
| Bi-210 | 83 | 127 | 83 |
This completes the step-by-step solution for determining the number of protons, neutrons, and electrons for the given atoms.
For each atom:
1. Identify the atomic number (number of protons)
2. Identify the mass number (sum of protons and neutrons)
3. Calculate the number of neutrons (mass number - atomic number)
4. Determine the number of electrons, which is equal to the number of protons in a neutral atom
Let's proceed with each element:
### a. Nb-94
- Nb (Niobium) has an atomic number of 41.
- Mass number is 94.
- Protons: 41
- Neutrons: 94 - 41 = 53
- Electrons: 41
### b. [tex]\( \text{Os-191} \)[/tex]
- Os (Osmium) has an atomic number of 76.
- Mass number is 191.
- Protons: 76
- Neutrons: 191 - 76 = 115
- Electrons: 76
### c. Pu-244
- Pu (Plutonium) has an atomic number of 94.
- Mass number is 244.
- Protons: 94
- Neutrons: 244 - 94 = 150
- Electrons: 94
### d. [tex]\( \text{ }_{15}^{31} P \)[/tex]
- P (Phosphorus) has an atomic number of 15.
- Mass number is 31.
- Protons: 15
- Neutrons: 31 - 15 = 16
- Electrons: 15
### e. Xe-132
- Xe (Xenon) has an atomic number of 54.
- Mass number is 132.
- Protons: 54
- Neutrons: 132 - 54 = 78
- Electrons: 54
### f. [tex]\( \text{ }_{83}^{210} Bi \)[/tex]
- Bi (Bismuth) has an atomic number of 83.
- Mass number is 210.
- Protons: 83
- Neutrons: 210 - 83 = 127
- Electrons: 83
### Summary
Here's a quick summary table:
| Element | Protons | Neutrons | Electrons |
|-------------|-------------|--------------|---------------|
| Nb-94 | 41 | 53 | 41 |
| P-31 | 15 | 16 | 15 |
| Os-191 | 76 | 115 | 76 |
| Xe-132 | 54 | 78 | 54 |
| Pu-244 | 94 | 150 | 94 |
| Bi-210 | 83 | 127 | 83 |
This completes the step-by-step solution for determining the number of protons, neutrons, and electrons for the given atoms.
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