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A 1250 kg car is pulling a 325 kg trailer. The car and trailer have an acceleration of [tex]2.15 \, \text{m/s}^2[/tex] together.

Determine the net force on the car-trailer combination. What is the net force on the trailer?

Answer :

To solve this problem we will apply the definition of Newton's second law, which says that force is equivalent to body mass by acceleration. In this case the mass of the trailer is 325Kg and its acceleration is [tex]2.15m / s ^ 2[/tex], so we will proceed to replace and multiply these values to find the net force on this object.

[tex]F= ma[/tex]

[tex]F= (325 kg)(2.15 m/s^2)[/tex]

F= 698.75N

Under the reference system in which the direction of travel is the positive direction, the direction of the force will be positive.

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Rewritten by : Barada

Final answer:

The net force on the car-trailer combination with a total mass of 1575 kg accelerating at 2.15 m/s² is 3386.25 N. The net force experienced by the trailer is the same as that of the combined system because it is being accelerated together with the car.

Explanation:

To determine the net force on the car-trailer combination with a mass of 1250 kg and 325 kg respectively, an application of Newton's second law of motion is required, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration (F = ma).

In this situation, the total mass (m) of the car-trailer system is the sum of the car and trailer masses: 1250 kg + 325 kg = 1575 kg. Given the acceleration (a) of the system is 2.15 m/s2, the net force on the combination can be calculated as:
F = (1575 kg) × (2.15 m/s2) = 3386.25 N

The net force on the trailer alone is not different because it is part of the combined system being accelerated at the same rate; therefore, it experiences the same force as the whole system. However, if you are looking for the force through the hitch that the car exerts on the trailer, additional information would be needed, such as the distribution of the resisting forces between the car and trailer.