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Answer :
Final answer:
The increase in potential energy of a 6.55 kg bowling ball lifted 2.40 m is calculated using the formula PE = mgh. The closest calculated answer is 154 J, which rounds the exact amount of 153.624 J.
Explanation:
The question is asking for the increase in potential energy of a bowling ball when it is lifted to a certain height. To calculate this, we use the formula for gravitational potential energy, which is PE = mgh, where 'm' is mass in kilograms, 'g' is the acceleration due to gravity (9.8 m/s2 on Earth), and 'h' is the height in meters. In this case, the bowling ball has a mass of 6.55 kg and is lifted 2.40 m into a storage rack.
Therefore, the increase in potential energy can be calculated as:
PE = (6.55 kg) × (9.8 m/s2) × (2.40 m) = 153.624 J.
Since this value is not exactly one of the options provided, the closest answer would be B) 154 J, which is the most accurate rounded option from the choices given.
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Answer:
B)154 J
Explanation:
Mass of bowling ball=m=6.55kg
Height of bowling ball from ground=h=2.4m
Acceleration due to gravity=[tex]g=9.8m/s^2[/tex]
We know that
Potential energy=mgh
Where m=Mass of object
g=Acceleration due to gravity
h=Height of object from ground
Substitute the values then we get
Potential energy=[tex]6.55\times 2.4\times 9.8=154J[/tex]
Hence, the increase in the ball's potential energy=154J
