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Answer :
To solve this problem, we need to find out how much time it takes for Omar to shell 5 pounds of peas, given the equation of the proportional relationship: [tex]\( y = 0.25x \)[/tex].
1. Understand the Given Equation:
The equation [tex]\( y = 0.25x \)[/tex] represents a proportional relationship where:
- [tex]\( y \)[/tex] is the weight of peas shelled in pounds.
- [tex]\( x \)[/tex] is the time spent shelling peas in minutes.
- 0.25 is the constant of proportionality, which tells us the weight in pounds per minute of time spent.
2. Set the Known Value:
We are told that Omar shells 5 pounds of peas, so we set [tex]\( y = 5 \)[/tex].
3. Solve for [tex]\( x \)[/tex]:
Plug the value of [tex]\( y \)[/tex] into the equation and solve for [tex]\( x \)[/tex]:
[tex]\[
5 = 0.25x
\][/tex]
To isolate [tex]\( x \)[/tex], divide both sides by the constant 0.25:
[tex]\[
x = \frac{5}{0.25}
\][/tex]
4. Perform the Division:
Dividing 5 by 0.25 gives:
[tex]\[
x = 20
\][/tex]
Therefore, it takes Omar 20 minutes to shell 5 pounds of peas.
1. Understand the Given Equation:
The equation [tex]\( y = 0.25x \)[/tex] represents a proportional relationship where:
- [tex]\( y \)[/tex] is the weight of peas shelled in pounds.
- [tex]\( x \)[/tex] is the time spent shelling peas in minutes.
- 0.25 is the constant of proportionality, which tells us the weight in pounds per minute of time spent.
2. Set the Known Value:
We are told that Omar shells 5 pounds of peas, so we set [tex]\( y = 5 \)[/tex].
3. Solve for [tex]\( x \)[/tex]:
Plug the value of [tex]\( y \)[/tex] into the equation and solve for [tex]\( x \)[/tex]:
[tex]\[
5 = 0.25x
\][/tex]
To isolate [tex]\( x \)[/tex], divide both sides by the constant 0.25:
[tex]\[
x = \frac{5}{0.25}
\][/tex]
4. Perform the Division:
Dividing 5 by 0.25 gives:
[tex]\[
x = 20
\][/tex]
Therefore, it takes Omar 20 minutes to shell 5 pounds of peas.
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