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At 80 °C, the volume of a gas is 38.6 mL. At the same pressure, its volume is 244 mL at what temperature?

A. 2000 °C
B. 2232.35 °C
C. 230 °C
D. -220 °C

Answer :

Answer:

The temperature is 2,231.36 K. (The closest value is 2,232.35K).

Explanation:

The given information from the exercise is:

- Initial temperature (T1): 80°C (353K)

- Initial volume (V1): 38.6mL

- Final volume (V2): 244mL

1st) It is necessary to convert the temperature unit from °C to K:

80+273 = 353K

2nd) Now we can calculate the final temperature (T2), by replacing the values of T1, V1 and V2 in the Charles's law formula:

[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \frac{38.6mL}{353K}=\frac{244mL}{T_2} \\ 0.10935\frac{mL}{K}=\frac{244mL}{T_2} \\ T_2=\frac{244mL}{0.10935\frac{mL}{K}} \\ T_2=2,231.36K \end{gathered}[/tex]

So, the temperature is 2,231.36 K. (The closest value is 2,232.35K).

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