Answer :

To find out how many grams of sucrose are in a 1.55 L solution with a concentration of 0.758 M (molarity), follow these steps:

1. Understand Molarity:
- Molarity (M) is defined as the number of moles of solute (in this case, sucrose) per liter of solution. It is given as 0.758 M, which means there are 0.758 moles of sucrose per liter of solution.

2. Calculate the Number of Moles of Sucrose:
- To find the number of moles of sucrose in 1.55 L of solution, use the formula:
[tex]\[
\text{moles of sucrose} = \text{Molarity} \times \text{Volume in Liters}
\][/tex]
- Plug in the values:
[tex]\[
\text{moles of sucrose} = 0.758 \, \text{M} \times 1.55 \, \text{L}
\][/tex]
- This results in approximately 1.1749 moles of sucrose.

3. Find the Molar Mass of Sucrose:
- The molar mass of sucrose (C₁₂H₂₂O₁₁) is the sum of the atomic masses of all the atoms in the formula. This total is approximately 342.3 g/mol.

4. Calculate the Mass of Sucrose in Grams:
- Use the formula:
[tex]\[
\text{mass in grams} = \text{moles of sucrose} \times \text{molar mass of sucrose}
\][/tex]
- Substitute the known values:
[tex]\[
\text{mass in grams} = 1.1749 \, \text{moles} \times 342.3 \, \text{g/mol}
\][/tex]
- This gives a mass of approximately 402.17 grams of sucrose.

Therefore, there are about 402.17 grams of sucrose in the 1.55 L of 0.758 M sucrose solution.

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