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Answer :
Answer:
924.376 Hz
Explanation:
Data provided in the question:
Velocity of the ambulance, v = 99.9 km/h = [tex]99.9 \times\frac{5}{18}[/tex] m/s
= 27.75 m/s
Frequency of the sound, f₀ = 786 Hz
Speed of the sound, V = 343 m/s
Now,
Using the Doppler's effect formula, we have
Frequency heard = [tex]f_0\times[\frac{V+v}{V-v}][/tex]
Thus,
Frequency heard = [tex]786\times[\frac{343+27.75}{343-27.75}][/tex]
or
Frequency heard = 786 × 1.176
or
Frequency heard = 924.376 Hz
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Answer:
The frequency is 924.3 Hz.
Explanation:
Given that,
Velocity of ambulance = 99.9 Km/h
Sound frequency = 786 Hz
We need to calculate the frequency
Using formula of frequency
[tex]f=f_{0}(\dfrac{v+v_{0}}{v-v_{0}})[/tex]
Where, v = speed of sound
v₀ = velocity of observer
f₀ = Observer frequency
Put the value into the formula
[tex]f=786\times(\dfrac{343+99.9\times\dfrac{5}{18}}{343-99.9\times\dfrac{5}{18}})[/tex]
[tex]f=924.3\ Hz[/tex]
Hence, The frequency is 924.3 Hz.
