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Answer :
Answer:
0.47 N
Explanation:
q1 = 3.4 x 10^-6 C
q2 = 2 x 10^-6 C
d = 17.5 cm = 0.175 m
The electrostatic force is given by
[tex]F=\frac{Kq_{1}q_{2}}{d^{2}}[/tex]
[tex]F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}[/tex]
F = 0.47 N
Thus, the force is 0.47 N.
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