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Answer :
Let's solve the problem step by step:
We need to find two consecutive numbers whose sum is 157. Let's say the first number is [tex]\( n \)[/tex].
Since the numbers are consecutive, the second number will be [tex]\( n + 1 \)[/tex].
According to the problem:
[tex]\[ n + (n + 1) = 157 \][/tex]
This simplifies to:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides of the equation:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78.
Therefore, the correct answer is:
B. 78
We need to find two consecutive numbers whose sum is 157. Let's say the first number is [tex]\( n \)[/tex].
Since the numbers are consecutive, the second number will be [tex]\( n + 1 \)[/tex].
According to the problem:
[tex]\[ n + (n + 1) = 157 \][/tex]
This simplifies to:
[tex]\[ 2n + 1 = 157 \][/tex]
Now, let's solve for [tex]\( n \)[/tex]:
1. Subtract 1 from both sides of the equation:
[tex]\[ 2n = 157 - 1 \][/tex]
[tex]\[ 2n = 156 \][/tex]
2. Divide both sides by 2:
[tex]\[ n = \frac{156}{2} \][/tex]
[tex]\[ n = 78 \][/tex]
So, the first number is 78.
Therefore, the correct answer is:
B. 78
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