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Answer :
To find the pH of a solution containing [tex]\(2.3 \times 10^{-2}\)[/tex] moles of [tex]\(H^+\)[/tex] ions, you can use the formula for pH, which is:
[tex]\[ \text{pH} = -\log_{10} [\text{H}^+] \][/tex]
Here's how you can calculate it step by step:
1. Identify the concentration of [tex]\(H^+\)[/tex] ions: The concentration is given as [tex]\(2.3 \times 10^{-2}\)[/tex] moles per liter.
2. Plug the concentration into the pH formula: You want to find [tex]\(-\log_{10} (2.3 \times 10^{-2})\)[/tex].
3. Calculate the logarithm: Find the base-10 logarithm of [tex]\(2.3 \times 10^{-2}\)[/tex].
4. Use the negative sign: Apply the negative in front of the logarithm result to find the pH.
After following these steps, the pH of the solution is approximately 1.64.
Therefore, the correct answer is D. 1.64.
[tex]\[ \text{pH} = -\log_{10} [\text{H}^+] \][/tex]
Here's how you can calculate it step by step:
1. Identify the concentration of [tex]\(H^+\)[/tex] ions: The concentration is given as [tex]\(2.3 \times 10^{-2}\)[/tex] moles per liter.
2. Plug the concentration into the pH formula: You want to find [tex]\(-\log_{10} (2.3 \times 10^{-2})\)[/tex].
3. Calculate the logarithm: Find the base-10 logarithm of [tex]\(2.3 \times 10^{-2}\)[/tex].
4. Use the negative sign: Apply the negative in front of the logarithm result to find the pH.
After following these steps, the pH of the solution is approximately 1.64.
Therefore, the correct answer is D. 1.64.
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