College

We appreciate your visit to You push a 1 30 kg physics book 2 80 m along a horizontal tabletop with a horizontal push of 1 55 N while the. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N, while the opposing force of friction is 0.340 N. How much work does your 1.55 N push do on the book?

Answer :

The work done by the 1.55 N push on the physics book over a distance of 2.80 m is 4.34 Joules.

The question involves calculating the work done by a push force on a physics book against friction. Work is defined as the product of the force and the distance moved in the direction of the force. Hence, the work done by the 1.55 N push on the book can be found by multiplying this force by the distance over which it acts, 2.80 m. It is given by the formula:

Work done = Force imes Distanc

Substituting the given values:

Work done = 1.55 N imes 2.80 m = 4.34 Joules

Thanks for taking the time to read You push a 1 30 kg physics book 2 80 m along a horizontal tabletop with a horizontal push of 1 55 N while the. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

Answer:

3.36J

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

= 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

Therefore the work of the 1.55N 3.36J