The net work done per engine cycle in a 4-stroke petrol internal combustion engine is 3500 J. The engine has 4 cylinders, and the crankshaft rotates at 3000 revolutions per minute (3000 rpm). Calculate:

(a) The number of cycles per second.

(b) The indicated power of the engine.

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Answer :

EmilyDonna EmilyDonna · Answer 1 · 2024-01-23T09:33:19-05:00

The answer to the given problem is:Given, The net work done per engine cycle in a 4-stroke petrol internal combustion engine is 3500 J.

Calculations:(a) The number of cycles per secondFrequency of the crankshaft = 3000 rev/mincycles per minute

= 3000 / 2 (stroke per cycle)

= 1500 cycles/min

The number of cycles per second = 1500 / 60

= 25 Hz(b) The indicated power of the engineWe know that,

Indicated power = (2πNT)/60*IPWhere,

N = number of cylindersT = torque produced by one cylinder per cycleI.P = Indicated pressure

For one cycle, work done = I.P × A × L

The net work done per engine cycle = 3500 J = I.P × A × L (where A is the area of the piston and L is the length of the stroke)

Let the force acting on the piston be F. Since work done per cycle is 3500 J For one cycle, work done = force × distance covered by the piston

W = FL∴ I.P × A × L

= FL∴ I.P = F / (A/L)Where A/L is the displacement of the engineFor one cylinder, the torque T = F × (A/2)For four cylinders, the torque

T4 = 4T = 4F × (A/2)

Indicated power = (2πNT4)/60 * IP

= [(2π × 3000 × 4 × 1/2) / 60] × 3500

= 22.6 kW

Thus, the frequency of the crankshaft is 25 Hz and the indicated power of the engine is 22.6 kW.

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