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Jerald jumped from a bungee tower. The equation that models his height, in feet, is [tex]h = -16t^2 + 729[/tex], where [tex]t[/tex] is the time in seconds. For which interval of time is he less than 104 feet above the ground?

A. [tex]t \gt 6.25[/tex]
B. [tex]-6.25 \lt t \lt 6.25[/tex]
C. [tex]t \lt 6.25[/tex]
D. [tex]0 \leq t \leq 6.25[/tex]

Answer :

To determine the interval of time during which Jerald is less than 104 feet above the ground, we need to analyze the equation given for Jerald's height:

[tex]\[ h = -16t^2 + 729 \][/tex]

We are interested in finding when his height is less than 104 feet, so we set up the inequality:

[tex]\[ -16t^2 + 729 < 104 \][/tex]

Step 1: Simplify the Inequality

Subtract 104 from both sides of the inequality:

[tex]\[ -16t^2 + 729 - 104 < 0 \][/tex]

This simplifies to:

[tex]\[ -16t^2 + 625 < 0 \][/tex]

Step 2: Isolate the Square Term

Subtract 625 from both sides:

[tex]\[ -16t^2 < -625 \][/tex]

Step 3: Solve for [tex]\( t^2 \)[/tex]

Divide each side of the inequality by -16. Remember, when you divide or multiply both sides of an inequality by a negative number, the inequality sign reverses:

[tex]\[ t^2 > \frac{625}{16} \][/tex]

Step 4: Solve for [tex]\( t \)[/tex]

Take the square root of both sides to solve for [tex]\( t \)[/tex]:

[tex]\[ t > \sqrt{\frac{625}{16}} \][/tex]

The square root of [tex]\(\frac{625}{16}\)[/tex] is [tex]\(\frac{25}{4}\)[/tex], which equals 6.25. Thus, we have:

[tex]\[ t > 6.25 \quad \text{or} \quad t < -6.25 \][/tex]

Since time [tex]\( t \)[/tex] typically starts from zero and we are considering a real-life scenario of jumping from a bungee tower (where negative time does not apply), we focus on the positive interval.

Therefore, the time interval during which Jerald is less than 104 feet above the ground is:

[tex]\[ t > 6.25 \][/tex]

This aligns with the choice from the options given: [tex]\( t > 6.25 \)[/tex].

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