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Answer :
Answer:
51,200
Step-by-step explanation:
a day and a half = 36 hours
36/4 = 9
There are 9 doubling periods
how many bacteria will there be in a day and a half?
100 * 2^9
100 * 512
51200
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Final answer:
To calculate the bacterial population after a day and a half with an initial count of 100 and a doubling time of 4 hours, we find 9 doubling periods in 36 hours. Using the exponential growth formula N = N0 * 2^n, we calculate the final population to be 51,200 bacteria.
Explanation:
The question involves an understanding of exponential growth, specifically concerning a population of bacteria. Given that the bacteria double in population every 4 hours, we first need to determine the number of doubling periods in a day and a half, which is equal to 36 hours. Since there are 4 hours in each doubling period, we divide 36 by 4 to get 9 doubling periods.
To find out the total number of bacteria after 36 hours, we use the formula for exponential growth:
N = N0 * 2^n
where N is the final population size, N0 is the initial population size, and n is the number of doubling periods.
Substituting the given values:
N = 100 * 2^9
N = 100 * 512
N = 51,200
Therefore, after a day and a half, there will approximately be 51,200 bacteria.
Learn more about Exponential Bacterial Growth here:
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