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The mayors of two small towns that adjoin a large community have engaged in an argument about which of their cities is safer with respect to its crime rate.

City A has a residential population of 123,000 people and reported 185 violent crimes. City B has a residential population of 84,000 people and reported 135 violent crimes.

Answer the following questions:

1. What is the reported crime rate per 100,000 residents in both cities?
2. Based on your responses to the previous question, which city has the lowest crime rate?

Answer :

Answer:

1. City A: 150 violent crimes per 100,000 residents.

City B: 161 violent crimes per 100,000 residents.

2. City A

Step-by-step explanation:

City A:

Population = 123,000

Violent crimes = 185

Violent crimes per 100,000 people:

[tex]V_{100k} = \frac{185*100,000}{123,000} \\V_{100k} = 150[/tex]

City B:

Population = 84,000

Violent crimes = 135

Violent crimes per 100,000 people:

[tex]V_{100k} = \frac{135*100,000}{84,000} \\V_{100k} = 161[/tex]

1. City A: 150 violent crimes per 100,000 residents.

City B: 161 violent crimes per 100,000 residents.

2. Even though it has a bigger number of crimes, City A has the lowest crime rate since its population is larger.

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Rewritten by : Barada

City A, with a crime rate of 150.41, has a lower crime rate compared to City B which has a rate of 160.71 per 100,000 residents.

To calculate the crime rate per 100,000 residents for each city, we use the following formula:

Crime Rate = (Number of Violent Crimes / Residential Population) x 100,000

For City A:

Crime Rate = (185 / 123,000) x 100,000 = 150.41

For City B:

Crime Rate = (135 / 84,000) x 100,000 = 160.71

After calculating the crime rates, we can determine which city has the lowest rate. City A has a crime rate of 150.41 while City B has a crime rate of 160.71. Therefore, City A has the lowest crime rate.