Answer :

The limiting reactant for the reaction of 35.8 grams of zinc, Zn and 12.9 grams of oxygen, O₂ is zinc, Zn

How to determine the limiting reactant for the reaction?

The following were obtained from the question:

  • Mass of Zn before reaction = 35.8 grams
  • Mass of O₂ before reaction = 12.9 grams
  • Limiting reactant =?

The limiting reactant for the reaction of 35.8 grams of zinc, Zn and 12.9 grams of oxygen, O₂ is determined as follow:

2Zn + O₂ -> 2ZnO

  • Molar mass of Zn = 65.38 g/mol
  • Mass of Zn from the balanced equation = 2 × 65.38 = 126.76 g
  • Molar mass of O₂ = 32 g/mol
  • Mass of O₂ from the balanced equation = 1 × 32 = 32 g

From the balanced equation above,

126.76 g of zinc, Zn reacted with 32 g of oxygen, O₂

Therefore,

35.8 g of zinc, Zn will react with = (35.8 × 32) / 126.76 = 9.04 g of oxygen, O₂

Now, we can see from the above that only 9.04 g of oxygen, O₂ took part in the reaction.

Thus, we can conclude that the limiting reactant is zinc, Zn

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