Answer :

If 97.5 mol of an ideal gas occupies 36.5 L at 463 K, then the pressure of the gas is 101.49 atm.

We know that the Ideal Gas Law states that

PV = nRT .... (i)

where P ⇒ Pressure

V ⇒ Volume

n ⇒ Number of moles

R ⇒ Ideal Gas Constant

T ⇒ Temperature

From the question, we know

V = 36.5 L

n = 97.5 mol

R = 0.08206 L atm mol⁻¹ K⁻¹

T = 463 K

If we put these values in equation (i), we get

P × 36.5 L = 97.5 mol × 0.08206 L atm mol⁻¹ K⁻¹ × 463 K

P = 97.5 mol × 0.08206 L atm mol⁻¹ K⁻¹ × 463 K / 36.5 L

P = 101.49 atm

Hence, if 97.5 mol of an ideal gas occupies 36.5 L at 463 K, then the pressure of the gas is 101.49 atm.

Learn more about ideal gas law:

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