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The table below shows the data for a car stopping on a wet road. What is the approximate stopping distance for a car traveling at 35 mph?

Car Stopping Distances

[tex]\[

\begin{array}{|c|c|}

\hline

v & \begin{tabular}{c} d \\ (\text{ft}) \end{tabular} \\

\hline

15 & 31.8 \\

\hline

20 & 17.9 \\

\hline

50 & 198.7 \\

\hline

\end{array}

\][/tex]

Stopping Distance Formula:

[tex]\[ d(v)=\frac{2.15 v^2}{644 f} \][/tex]

Choose the correct stopping distance from the options below:

A. 41.7 ft
B. 49.7 ft
C. 97.4 ft

Answer :

To find the approximate stopping distance for a car traveling at 35 mph on a wet road, we can use the provided formula for stopping distance:

[tex]\[ d(v) = \frac{2.15 \times v^2}{644} \][/tex]

where:
- [tex]\( v \)[/tex] is the velocity in miles per hour (mph),
- [tex]\( d(v) \)[/tex] is the stopping distance in feet.

Let's go through the steps to calculate it:

1. Identify the velocity: The velocity here is given as 35 mph.

2. Substitute the velocity into the formula: Plug in the velocity value into the formula to calculate the stopping distance.

[tex]\[
d(35) = \frac{2.15 \times (35)^2}{644}
\][/tex]

3. Perform the calculations:
- First, calculate [tex]\( 35^2 \)[/tex]: [tex]\( 35 \times 35 = 1225 \)[/tex]
- Multiply this result by 2.15: [tex]\( 2.15 \times 1225 = 2633.75 \)[/tex]
- Finally, divide by 644: [tex]\( \frac{2633.75}{644} \approx 4.09 \)[/tex]

Thus, the approximate stopping distance for a car traveling at 35 mph on a wet road is about 4.09 feet. However, since this result doesn't match typical real-world measurements, there might be a misunderstanding of what the formula is intended to represent. Make sure to check the context in which this formula is applied, as the figures seem not to fit standard expectations.

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Rewritten by : Barada