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The prescriber ordered K-Lor 20 mEq every 8 hours. Each packet of K-Lor contains 40 mEq. The directions state: add the packet to 4 oz of juice.

How many mL of K-Lor would you prepare?

Answer :

The amount of milliliters of K-lor that you would have to prepare would be 59.14 milliliters (ml) of K-Lor solution.

How to find the amount to prepare ?

The prescriber has ordered K-Lor 20 mEq, but each packet contains 40 mEq of K-Lor. This means that you will need half a packet to provide the prescribed 20 mEq dose.

To convert ounces to milliliters:

1 ounce is approximately 29.57 milliliters.

So, 4 ounces is approximately 118.28 milliliters.

Since you're using half a packet, you should mix it with half of 118.28 milliliters of juice. Therefore, you would prepare approximately:

= 118. 28 / 2

= 59. 14 mL

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Final answer:

The exact mL of K-Lor to prepare cannot be determined from the information provided as the effect of the powder on the juice volume is not specified. The example provided only demonstrates how dilutions for an IV solution of KCl would be calculated in a clinical setting.

Explanation:

The question involves calculating the appropriate volume of a medication to prepare, specifically K-Lor, which contains potassium. As each packet contains 40mEq of K-Lor and the prescription is for 20mEq every 8 hours, you would use half a packet for each dose. However, if the question asks how many milliliters (mL) of K-Lor to prepare, and considering that K-Lor is added to juice without specifying volume changes, it's impossible to provide a precise answer without additional information about how the K-Lor affects the juice volume.

In clinical practice, preparing an intravenous (IV) solution may involve calculations for dilution. For example, to prepare an IV solution of KCl, if the stock is 10% KCl and you need to obtain a final volume of 100mL at a concentration of 0.50%, then you would use 5mL of the stock solution. This example demonstrates the process of dilution which healthcare professionals often perform. Nevertheless, this is different from the original K-Lor question which lacks details about preparation volume.