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Answer :
Final answer:
To produce 100.0 g of SO2, approximately 68.64 grams of O2 are required.
option c is correct
Explanation:
To calculate the mass of O2 required to produce 100.0 g of SO2, we need to use the stoichiometric ratio between FeS2 and O2 from the balanced chemical equation.
The molar mass of O2 is 32.00 g/mol, and the molar mass of SO2 is 64.06 g/mol.
First, we calculate the number of moles of SO2:
moles of SO2 = mass of SO2 / molar mass of SO2
moles of SO2 = 100.0 g / 64.06 g/mol = 1.560 mol
Next, we use the stoichiometric ratio to find the number of moles of O2:
moles of O2 = (moles of SO2) x (moles of O2 / moles of SO2)
moles of O2 = 1.560 mol x (11 mol O2 / 8 mol SO2) = 2.145 mol
Finally, we calculate the mass of O2:
mass of O2 = moles of O2 x molar mass of O2
mass of O2 = 2.145 mol x 32.00 g/mol = 68.64 g
Learn more about calculating the mass of o2 required to produce a given mass of so2 here:
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