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Answer :
The fullback's momentum before the collision was 779 kg m/s, the change in his momentum was -779 kg m/s, and the tackle's original momentum was the same magnitude but opposite in direction. The tackle's original speed was 6.08 m/s.
To answer your questions regarding the 95kg fullback and the 128kg defensive tackle, we will use the principles of momentum in physics. Firstly, remember that momentum (p) is the product of mass (m) and velocity (v), expressed as p = m imes v.
- The fullback's momentum before the collision is calculated as momentum = mass * velocity, which gives us momentum = 95kg * 8.2m/s = 779 kg * m/s.
- The change in the fullback's momentum is the difference between the final momentum and the initial momentum. Since the final momentum after the collision is zero (as both players end up with zero speed), the change is -779 kg * m/s (a decrease).
- The change in the tackle's momentum must be equal in magnitude and opposite in direction to the change in the fullback's momentum due to the conservation of momentum, so it is also 779 kg * m/s (but in the opposite direction).
- To find the tackle's original momentum, we use the conservation of momentum which states that the total momentum before the collision equals the total momentum after. Since they both end up with zero speed, the total initial momentum was zero, therefore the tackle's original momentum was -779 kg * m/s.
- Lastly, to find the tackle's original speed, we rearrange the momentum equation to solve for velocity: velocity = momentum/mass, which gives us the original speed of the tackle = -779 kg * m/s / 128kg \6.08 m/s.
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