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A 93-kg water skier floating in a lake is pulled from rest to a speed of 10 m/s over a distance of 28 m.

What is the work done on the skier?

Answer :

Final answer:

To find the acceleration of the water skier, we can use the equation v^2 = u^2 + 2as where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Explanation:

In this problem, we are given the mass of the water skier (93 kg), the initial speed (0 m/s), and the final speed (10 m/s). We are also given the distance traveled (28 m). To find the acceleration of the skier, we can use the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.

Plugging in the known values, we have (10 m/s)^2 = (0 m/s)^2 + 2a(28 m).

Simplifying the equation, we get 100 = 56a.

Dividing both sides by 56, we find that the acceleration of the water skier is approximately 1.79 m/s^2.

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