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Answer :
Final answer:
The ΔG° can be calculated using the equation ΔG° = -RT ln K, where K is the equilibrium constant. By substituting the given values into the equation, the ΔG° for the reaction can be determined as -96.8 kJ mol-¹. The correct answer is d. 97.3 kJ.
Explanation:
The question asks to evaluate δg0 at 718oc for a gas phase reaction for which kp = 7.4 x 10-6 at 718oc and r = 8.314 j/mol k.
To solve this, we can use the equation ΔG° = -RT ln K.
By substituting the given values into the equation, we can calculate the ΔG° for the reaction. ΔG° = (-8.314 J K mol-¹)(718 K)(ln(7.4 × 10-6)) = -96.8 kJ mol-¹.
Therefore, the answer is d. 97.3 kJ.
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