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Calculate the energy transferred by an appliance using mains electricity ([tex]230V[/tex]) if the charge is [tex]150C[/tex]. Give your answer in kilojoules to three significant figures.

Answer :

The energy transferred by an appliance using mains electricity of 230V with a charge of 150C is 34.5 kJ.

Calculation of Energy Transferred by an Appliance

To calculate the energy transferred by an appliance using mains electricity, you can use the formula:

[tex]E = V * Q[/tex]

Where:

V is the voltage (230V in this case).

Q is the charge (150C here).

Plugging in the given values:

[tex]E = 230V * 150C = 34500J[/tex]

Since the question asks for the energy in kilojoules (kJ), we need to convert joules to kilojoules.

We know that [tex]1 kJ = 1000 J.[/tex]

So, [tex]34500 J = 34.5 kJ[/tex]

Therefore, the energy transferred by the appliance is 34.5 kJ.

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Rewritten by : Barada

Final answer:

The energy transferred by an electrical appliance using 230V with a charge of 150C is 34.5 kilojoules.

Explanation:

To calculate the energy transferred by an appliance using mains electricity, you would use the equation for calculating electrical energy. This is given by the formula E = V * Q, where E represents energy, V represents voltage and Q represents charge.

In this case, we are given a voltage V of 230 Volts and a charge Q of 150 Coulombs. To calculate the energy transferred, you multiply voltage and charge, which provides the energy in joules:

E = V * Q = 230V * 150C = 34500 Joules

However, we want the answer in kilojoules, (1kJ = 1000J), so we would need to convert this. By dividing by 1000, we get the energy as:

E = 34500J / 1000 = 34.5 kJ

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