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Answer :
(a) The resistance (in ω) of fifteen 215 ω resistors connected in series is 3225 ω.
(b) The resistance (in ω) of fifteen 215 ω resistors connected in parallel is 14.33 ω.
(a) When resistors are connected in series, their total resistance (in ω) can be calculated by simply adding their individual resistances. So, for fifteen 215 ω resistors connected in series:
Total Resistance = 15 × 215 ω = 3225 ω
(b) When resistors are connected in parallel, the total resistance (in ω) can be calculated using the following formula:
1 / Total Resistance = 1/R1 + 1/R2 + ... + 1/Rn
For fifteen 215 ω resistors connected in parallel:
1 / Total Resistance = 15 × (1/215)
Total Resistance = 1 / (15 × (1/215))
Total Resistance ≈ 14.333 ω
So, the total resistance for fifteen 215 ω resistors connected in parallel is approximately 14.333 ω.
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