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Answer :
Answer:
12 : 3 : 1
Explanation:
According to Mendel's principles, a dihybrid cross between two heterozygous summer squash parents (WwGg X WwGg) should yield offsprings, 12 with white, 3 with yellow and 1 with green color phenotype. The classic Mendelian phenotypic ratio for dihybrid cross is 9:3:3:1. In this case, genotypes W- G- and W- gg produce white color phenotype. This is because we have 12: 3: 1 phenotypic ratio in which the alleles of two different genes assort independently into gametes.
Dihybrid cross for heterozygous summer squash:
WG Wg wG wg
WG WWGG WWGg WwGG WwGg
Wg WWGg WWgg WwGg Wwgg
wG WwGG WwGg wwGG wwGg
wg WwGg Wwgg wwGg wwgg
Genotypes:
W-G- and W- gg = white = 12
ww G- = yellow = 3
ww gg = green = 1
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Final answer:
The ratio of white:yellow:green progeny from the cross Ww Gg × Ww Gg is 9:3:4, according to the pattern of inheritance in a Punnett square for a dihybrid cross.
Explanation:
The genotypes for a cross between Ww Gg and Ww Gg can be predicted using a Punnett square, which is a graphical representation used to predict the genotypes of offspring in a genetics problem. Here, the independence of the W and G genes is important.
If you construct a Punnett square for this dihybrid cross, you'll find that the resulting genotypic ratio of the offspring is 9:3:3:1. In the context of the squash color genotypes, the 9 represents white (W-_G- and W-_gg), 3 represents yellow (ww G-), and 4 represents green (3 from the '3' in the 9:3:3:1 ratio and an additional 1 from the '1' in the 9:3:3:1 ratio).
So the phenotypic ratio of white:yellow:green progeny from the cross Ww Gg × Ww Gg would be 9:3:4.
Learn more about Genotypic Ratio here:
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