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Answer :
Final answer:
The internal resistance of the cell in the first scenario is 1.5 Ω. In the second scenario, the resulting battery will have an emf of 2 V and an internal resistance of 0.1 Ω.
Explanation:
To calculate the internal resistance of a cell, we can use the formula: r = (V - V') / I, where r is the internal resistance, V is the battery voltage, V' is the voltage across the resistor, and I is the current.
In the first scenario, we are given a current of 0.4 A, a battery voltage of 6 V, and a resistor of 13.5 Ω. Using Ohm's Law, we can calculate the voltage across the resistor: V' = IR = 0.4 A * 13.5 Ω = 5.4 V.
Substituting the values into the formula, we get: r = (6 V - 5.4 V) / 0.4 A = 0.6 V / 0.4 A = 1.5 Ω.
Therefore, the internal resistance of the cell is 1.5 Ω.
In the second scenario, we are given five cells connected in parallel, each with an emf of 2 V and an internal resistance of 0.5 Ω. When cells are connected in parallel, the emf remains the same, but the internal resistance decreases. Therefore, the resulting battery will have an emf of 2 V and a total internal resistance of 0.5 Ω / 5 = 0.1 Ω.
Therefore, the correct answer is (C) an emf of 2 V and an internal resistance of 0.1 Ω.
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