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A helicopter of mass 6 tons moves vertically upwards with uniform acceleration. It covers a distance of 196 meters in 20 seconds from the start of its motion, against a resistance of 300 kg.wt. per ton of its mass. Calculate the motive force of the motor of the helicopter upwards in kg.wt.

Answer :

The aeroplane has an upwards motive force of 8400 kg.wt. This was calculated by determining the acceleration, net force, and resistive force, and then summing these with the gravitational force. The resistive force and gravitational force are key components in this calculation.

Let's start by calculating the acceleration:

The kinematic equation is:
s = ut + 0.5at²
Given that initial velocity, u = 0 (starts from rest), distance s = 196 m, and time t = 20 s:
196 = 0 + 0.5 * a * 20²
196 = 200a
a = 196/200
a = 0.98 m/s²

Next, we calculate the net force:

The mass of the aeroplane = 6 tons = 6000 kg.
Using Newton's second law, F = ma:
F = 6000 kg * 0.98 m/s²
F = 5880 N


Converting this to kg.wt (since 1 kg.wt = 9.8 N):
F = 5880 N / 9.8 N/kg.wt = 600 kg.wt

Now, calculate the resistive force:

Given 300 kg.wt resistance per ton of mass:
Resistive Force = 300 kg.wt/ton * 6 tons
Resistive Force = 1800 kg.wt

Finally, we calculate the total motive force:

Total force required to lift the aeroplane = Motive force - Resistive force - Gravitational force


Gravitational force = Weight of the aeroplane = 6000 kg * 9.8 N/kg.wt = 6000 kg.wt
Total motive force = Net force + Resistive force + Gravitational force
Total motive force = 600 kg.wt + 1800 kg.wt + 6000 kg.wt
Total motive force = 8400 kg.wt

Therefore, the motive force of the motor of the aeroplane upwards is 8400 kg.wt.

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