A concentrated solution of phosphoric acid, [tex]$H_3PO_4$[/tex], has a concentration of 14.6 M, and the solution has a density of 1.69 g/mL. What is the molality of the solution?

Question

27-09-2024
Chemistry

High School

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A concentrated solution of phosphoric acid, [tex]$H_3PO_4$[/tex], has a concentration of 14.6 M, and the solution has a density of 1.69 g/mL. What is the molality of the solution?

Answer :

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priyankakasturiase50 priyankakasturiase50 · Answer 1 · 2025-02-20T07:04:36-05:00

Final answer:

We can calculate molality by converting molarity and density to moles of solute and mass of solvent. However, the proposed solution approximates the weight of 1L of water to be 1kg, which may impact the accuracy of the result.

Explanation:

The molality of a solution is calculated by the ratio of the number of moles of the solute (in this case, phosphoric acid H3PO4) to the mass of the solvent (usually water) in kilograms.
Since we have the molarity and density, we can convert these into moles and mass respectively. One molar (M) is one mole per liter, and our solution has 14.6 M of phosphoric acid, so we have 14.6 mol/L. The density of the solution is 1.69 g/mL which can be converted to 1690 kg/m3.
However, molality only accounts for the mass of the solvent (water), not the total solution.
So assuming the weight of 1L water is approximately 1 kg, we can subtract it from the total weight of the solution to get the weight of phosphoric acid. Then, the molality can be calculated by dividing the moles of phosphoric acid by the weight of water in kg.

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