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Answer :
The new charge on the positive plate would be 9.75 x 10⁻⁷ C.
A capacitor is connected to a 1.5V battery and we need to calculate the charge on the capacitor.
Capacitance is 1.3µF.
The formula for calculating the charge on a capacitor is given as:
Q = CV
Where, Q = Charge on capacitor, C = Capacitance, and V = Voltage.
Substitute the given values in the above formula,
Q = (1.3 x 10⁻⁶) x (1.5)
Q = 1.95 x 10⁻⁶ C
The charge on the capacitor is 1.95 x 10⁻⁶ C.
To find the new charge on the positive plate when the potential
difference is halved, we can use the formula,
Q = CV
Substitute the given values in the above formula,
Q = (1.3 x 10⁻⁶) x (0.75)
Q = 9.75 x 10⁻⁷ C
The new charge on the positive plate would be 9.75 x 10⁻⁷ C.
To learn more about Capacitance from the given link.
https://brainly.com/question/21851402
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