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Wolves are sometimes observed to have black coats and blue eyes. Grey coat color (N) is dominant to black (n), and brown eyes (B) are dominant to blue (b). Suppose the alpha female of a pack is NnBb, and her mate is homozygous recessive for coat color and heterozygous for eye color.

What is the statistical likelihood of them producing a pup with a grey coat and blue eyes?

A. 2/16
B. 4/16
C. 6/16
D. 16/16

Answer :

The statistical likelihood of the alpha female and her mate producing a pup with a grey coat and blue eyes is 4/16.

B. Explanation: To determine the likelihood of producing a pup with a grey coat and blue eyes, we need to consider the inheritance patterns of coat color and eye color in wolves. The alpha female is NnBb, which means she carries one dominant allele for grey coat color (N) and one dominant allele for brown eyes (B). Her mate, on the other hand, is homozygous recessive for coat color (nn) and heterozygous for eye color (Bb).

When these two wolves mate, there are four possible combinations of alleles that the pup can inherit: NnBb, Nnbb, nnBb, and nnbb. Out of these four combinations, only one combination (Nnbb) will result in a grey coat (Nn) and blue eyes (bb), as the grey coat color (N) is dominant over black (n), and brown eyes (B) are dominant over blue (b).

Therefore, the probability of the pup having a grey coat and blue eyes is 1 out of 4 possible combinations, which can be simplified to 1/4 or 4/16.

In summary, the statistical likelihood of the alpha female and her mate producing a pup with a grey coat and blue eyes is 4/16.

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