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Answer :
Final answer:
The final molarity of the solution prepared by diluting 25.0 mL of a 2.10 M AgNO3 to a final volume of 98.5 mL is 0.53 M.
Explanation:
The question asks to determine the molarity of a solution after dilution.
To calculate the new molarity after dilution, the dilution equation M1V1 = M2V2 can be used, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the final solution, respectively.
In this case, the initial molarity (M1) is 2.10 M, the initial volume (V1) is 25.0 mL, and the final volume (V2) after dilution to 98.5 mL is given. We need to find the final molarity (M2).
Using the equation:
(2.10 M)(25.0 mL) = M2(98.5 mL)
We solve for M2:
M2 = (2.10 M × 25.0 mL) / 98.5 mLM2 = 0.53 M (rounded to two decimal places)
The final concentration of the AgNO3 solution after dilution is 0.53 M.
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