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Write a function to describe the following scenario:

A garden watering bucket has 3000 milliliters of water in it, but there is a hole that is leaking 18 milliliters every minute. How much water remains in the container after a certain number of minutes?

[tex] y = 3000 - 18x [/tex]

Answer :

To describe the scenario of the leaking garden watering bucket, we can set up a simple linear equation. Here's how you can think about it:

1. Initial Amount: The bucket starts with 3000 milliliters of water.

2. Leak Rate: The bucket leaks 18 milliliters of water per minute.

3. Time: Let [tex]\( x \)[/tex] represent the number of minutes that pass.

4. Water Lost: For each minute, 18 milliliters is lost through the leak. So, after [tex]\( x \)[/tex] minutes, the total amount of water lost is [tex]\( 18 \times x \)[/tex].

5. Remaining Water: To find out how much water remains in the bucket after [tex]\( x \)[/tex] minutes, subtract the total water lost from the initial amount of water.

The equation for the remaining water [tex]\( y \)[/tex], after [tex]\( x \)[/tex] minutes is:

[tex]\[ y = 3000 - 18x \][/tex]

Here, [tex]\( y \)[/tex] is the amount of water left in the bucket, [tex]\( 3000 \)[/tex] is the initial milliliters of water, [tex]\( 18 \)[/tex] is the leak rate per minute, and [tex]\( x \)[/tex] is the number of minutes that have passed. This formula helps you calculate how much water remains in the bucket at any given time [tex]\( x \)[/tex].

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