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Answer :
To solve the chemical equations provided, we need to balance them. Balancing chemical equations ensures the same number of each type of atom appears on both sides of the equation, following the law of conservation of mass.
1. Balancing the equation: Sr + O₂ → SrO
- Step 1: Count the atoms on each side.
- Reactants: 1 Sr, 2 O
- Products: 1 Sr, 1 O
- Step 2: Balance the oxygen atoms. Since there are 2 oxygen atoms on the reactant side (O₂), you need 2 SrO on the product side to provide 2 oxygen atoms.
- Sr + O₂ → 2 SrO
- Step 3: Balance the strontium atoms. Now, you have 2 Sr on the product side, so you need 2 Sr on the reactant side.
- 2 Sr + O₂ → 2 SrO
This equation is now balanced with 2 Sr and 2 O on both sides.
2. Balancing the equation: Sn + NaOH → Na₂SnO₂ + H₂
- Step 1: Count the atoms on each side.
- Reactants: 1 Sn, 1 Na, 1 O, 1 H
- Products: 2 Na, 1 Sn, 2 O, 2 H
- Step 2: Balance the sodium (Na) atoms. There are 2 Na atoms in Na₂SnO₂ on the product side, so you need 2 NaOH on the reactant side.
- Sn + 2 NaOH → Na₂SnO₂ + H₂
- Step 3: Balance the oxygen and hydrogen atoms. With 2 NaOH, you have 2 O and 2 H on the reactant side, which already matches the product side.
- Step 4: Ensure the tin (Sn) atoms are balanced. There’s 1 Sn on each side, which is already balanced.
The balanced equation is:
- Sn + 2 NaOH → Na₂SnO₂ + H₂
These balanced equations ensure the conservation of mass is upheld in these chemical reactions.
1. Balancing the equation: Sr + O₂ → SrO
- Step 1: Count the atoms on each side.
- Reactants: 1 Sr, 2 O
- Products: 1 Sr, 1 O
- Step 2: Balance the oxygen atoms. Since there are 2 oxygen atoms on the reactant side (O₂), you need 2 SrO on the product side to provide 2 oxygen atoms.
- Sr + O₂ → 2 SrO
- Step 3: Balance the strontium atoms. Now, you have 2 Sr on the product side, so you need 2 Sr on the reactant side.
- 2 Sr + O₂ → 2 SrO
This equation is now balanced with 2 Sr and 2 O on both sides.
2. Balancing the equation: Sn + NaOH → Na₂SnO₂ + H₂
- Step 1: Count the atoms on each side.
- Reactants: 1 Sn, 1 Na, 1 O, 1 H
- Products: 2 Na, 1 Sn, 2 O, 2 H
- Step 2: Balance the sodium (Na) atoms. There are 2 Na atoms in Na₂SnO₂ on the product side, so you need 2 NaOH on the reactant side.
- Sn + 2 NaOH → Na₂SnO₂ + H₂
- Step 3: Balance the oxygen and hydrogen atoms. With 2 NaOH, you have 2 O and 2 H on the reactant side, which already matches the product side.
- Step 4: Ensure the tin (Sn) atoms are balanced. There’s 1 Sn on each side, which is already balanced.
The balanced equation is:
- Sn + 2 NaOH → Na₂SnO₂ + H₂
These balanced equations ensure the conservation of mass is upheld in these chemical reactions.
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