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Answer :
Final answer:
To produce 100 ounces of a 43 cid solution, 52 ounces of a 55 cid solution and 48 ounces of a 30 cid solution need to be mixed, which is not represented by any of the given options (a through d).
Explanation:
The question asks how many ounces of a 55 cid solution and a 30 cid solution must be mixed to produce 100 ounces of a 43 cid solution. This is a typical mixture problem that can be solved by setting up an equation based on the concentration of the cid in each solution and the total cid needed in the final mixture.
To solve this, let's denote x as the amount of 55 cid solution needed and y as the amount of 30 cid solution needed. The total final mixture required is 100 oz, so we can establish the following equations based on the total volume and total amount of cid:
x + y = 100 (Total solution volume)
55x + 30y = 43(100) (Total cid in the solution)
Now we need to solve this system of equations. From the first equation, we can express y in terms of x: y = 100 - x.
Substituting this into the second equation gives us:
55x + 30(100 - x) = 4300
55x + 3000 - 30x = 4300
25x = 1300
x = 52 oz of 55 cid solution
And y = 100 - 52 = 48 oz of 30 cid solution
Therefore, 52 ounces of a 55 cid solution and 48 ounces of a 30 cid solution must be mixed to produce 100 ounces of a 43 cid solution, indicating that none of the options given (a through d) is correct.
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