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Answer :
The rotational kinetic energy of the propeller, modeled as a slender rod, is approximately 1,936,904 Joules, based on its moment of inertia and angular velocity.
To find the rotational kinetic energy, we use the formula:
Rotational Kinetic Energy (K) = (1/2) * I * ω²
First, we need to determine the moment of inertia (I) of the slender rod about its center:
I = (1/12) * m * L²
Where:
m = 122 kg
L = 1.98 m
I = (1/12) * 122 kg * (1.98 m)² = 39.19 kg•m²
Next, convert the angular velocity (ω) from rpm to rad/s:
ω = (3000 rev/min) * (2π rad/rev) * (1 min/60 s) = 314 rad/s
Now, we can calculate the rotational kinetic energy:
K = (1/2) * 39.19 kg•m² * (314 rad/s)² = 1,936,904 J
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