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A smoke jumper jumps from a plane that is 1500 feet above the ground. The function [tex] h = -16t^2 + 1500 [/tex] gives the jumper's height \( h \) in feet during free fall at \( t \) seconds.

Answer :

The smoke jumper will reach the ground after approximately t = (5√6) / 2 seconds.

The function h = -16t² + 1500 represents the height of a smoke jumper, in feet, above the ground at time t in seconds during a free fall.

To find the time it takes for the smoke jumper to reach the ground, we need to set the height h equal to 0 and solve for t.

0 = -16t² + 1500

To solve this quadratic equation, we can use the quadratic formula:

t = (-b ± √(b² - 4ac)) / (2a)

In this case, a = -16, b = 0, and c = 1500.

t = (-0 ± √(0² - 4(-16)(1500))) / (2(-16))

Simplifying further:

t = ± √(0 - (-96000)) / (-32)

t = ± √(96000) / (-32)

t = ± √(2400) / (-8)

t = ± (20√6) / (-8)

Simplifying the expression:

t = ± (5√6) / 2

Since time cannot be negative in this context, we can ignore the negative solution.

Therefore, the smoke jumper will reach the ground after approximately t = (5√6) / 2 seconds.

Learn more about quadratic equation visit:

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