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find the limit of each function (a) as x → [infinity] (b) as x →-[infinity] . (You may wish to visualize your answer with graphing calculator or computer.) 3. f(x) = 2/x - 3 4. f(x) = π -2/x² 6. g(x) = 1 / 8 – (5/x²) 5. g(x) = 1 / 2 + (1/x)

Answer :

Final answer:

To find the limit of each function as x approaches infinity and negative infinity, we analyze the behavior of the terms with x. The limit of each function as x approaches infinity is determined by the behavior of the term with the highest power of x. The limit of each function as x approaches negative infinity is also determined by the behavior of the term with the highest power of x.

Explanation:

(a) as x → ∞

For function 3: f(x) = 2/x - 3

As x approaches infinity, the term 2/x approaches 0, since x becomes very large. Therefore, the limit of f(x) as x approaches infinity is -3.

For function 4: f(x) = π - 2/x²

As x approaches infinity, the term 2/x² approaches 0, since x becomes very large. Therefore, the limit of f(x) as x approaches infinity is π.

For function 6: g(x) = 1 / 8 – (5/x²)

As x approaches infinity, the term 5/x² approaches 0, since x becomes very large. Therefore, the limit of g(x) as x approaches infinity is 1/8.

(b) as x → -∞

For function 3: f(x) = 2/x - 3

As x approaches negative infinity, the term 2/x approaches 0, since x becomes very large in magnitude. Therefore, the limit of f(x) as x approaches negative infinity is -3.

For function 4: f(x) = π - 2/x²

As x approaches negative infinity, the term 2/x² approaches 0, since x becomes very large in magnitude. Therefore, the limit of f(x) as x approaches negative infinity is π.

For function 6: g(x) = 1 / 8 – (5/x²)

As x approaches negative infinity, the term 5/x² approaches 0, since x becomes very large in magnitude. Therefore, the limit of g(x) as x approaches negative infinity is 1/8.

Keywords:

  • limit
  • as x approaches infinity
  • as x approaches negative infinity

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