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Answer :
Final answer:
In the phenomenon of capillary action, the mass of water rising in a capillary of radius 2r will still be 5g despite the radius change. This is because the mass of water depends on its volume and density, not the capillary's radius. With a larger tube, the water will rise less high but occupy more horizontal space, retaining a total mass of 5g.
Explanation:
The phenomenon you're referring to is called capillary action, which is a physical process that allows liquids to flow in narrow spaces without external assistance or against gravity. It's important to note that the mass of the water that will rise in the second tube of radius 2r will still be 5g, despite the change in radius.
This is because the mass of the water is determined by the volume of the water inside the tube and the density of the water, not the radius of the tube itself. By applying the formula 2T cos 0 h = rpg, where T is the surface tension of the water, r is the radius of the tube, p is the density of the water, and g is the acceleration due to gravity, we can understand that as r increases, the height h that the water rises to will decrease proportionally so that the equation stays balanced.
In other words, the water in the larger tube will not rise as high, but it will take up more space horizontally, ensuring that the overall mass of the water in the tube stays at 5g.
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