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A triangle has an area of [tex]$38.4 \, \text{cm}^2$[/tex]. The height of the triangle is 12.8 centimeters. What is the length of the base of the triangle?

Answer :

To solve this problem, we need to find the length of the base of a triangle given its area and height.

The formula for the area of a triangle is:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \][/tex]

We are given:
- The area of the triangle is [tex]\( 38.4 \, \text{cm}^2 \)[/tex].
- The height of the triangle is [tex]\( 12.8 \, \text{cm} \)[/tex].

We need to find the length of the base. To do this, we can rearrange the formula to solve for the base:

[tex]\[ \text{base} = \frac{2 \times \text{Area}}{\text{height}} \][/tex]

Now, substituting the given values into the formula:

[tex]\[ \text{base} = \frac{2 \times 38.4}{12.8} \][/tex]

[tex]\[ \text{base} = \frac{76.8}{12.8} \][/tex]

[tex]\[ \text{base} = 6 \][/tex]

Therefore, the length of the base of the triangle is [tex]\( 6 \, \text{cm} \)[/tex].

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