We appreciate your visit to Two blocks of ice collide elastically A 10 0 kg block of ice is sliding due east at 8 00 m s when it collides. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The final velocity of the 10.0 kg block of ice after the elastic collision is 5.00 m/s according to the principle of conservation of momentum.
Explanation:
This is a Physics problem dealing with elastic collisions in one dimension. The main principle that will be used to solve this is the conservation of momentum. The equation for conservation of momentum is m1v1 + m2v2 = m1v1' + m2v2', where the primes indicate the values after the collision. In this situation, we have to solve for v1', the final velocity of the 10.0 kg block of ice.
Filling the data we have, 10kg * 8 m/s + 6 kg * 4 m/s = 10kg * v1' + 6 kg* (-4 m/s). Solving this equation, we find that the final velocity v1' of the 10.0 kg block of ice is 5.00 m/s.
So the correct option is Option 2: 5.00 m/s.
Learn more about Elastic Collisions here:
https://brainly.com/question/33268757
#SPJ11
Thanks for taking the time to read Two blocks of ice collide elastically A 10 0 kg block of ice is sliding due east at 8 00 m s when it collides. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
