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Answer :
To determine which fraction is equivalent to [tex]\(\frac{7}{8}\)[/tex], we need to find a fraction among the choices that has the same value when simplified.
Let's look at each fraction one by one:
1. [tex]\(\frac{14}{18}\)[/tex]:
- Simplify [tex]\(\frac{14}{18}\)[/tex] by finding the greatest common divisor (GCD) of the numerator and the denominator:
- The GCD of 14 and 18 is 2.
- Divide both the numerator and the denominator by 2: [tex]\(\frac{14 \div 2}{18 \div 2} = \frac{7}{9}\)[/tex].
- [tex]\(\frac{7}{9}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{14}{18}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
2. [tex]\(\frac{13}{15}\)[/tex]:
- The GCD of 13 and 15 is 1 (because 13 is a prime number and doesn't divide 15), so [tex]\(\frac{13}{15}\)[/tex] is already in its simplest form.
- [tex]\(\frac{13}{15}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{13}{15}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
3. [tex]\(\frac{14}{16}\)[/tex]:
- Simplify [tex]\(\frac{14}{16}\)[/tex] by finding the GCD of the numerator and the denominator:
- The GCD of 14 and 16 is 2.
- Divide both the numerator and the denominator by 2: [tex]\(\frac{14 \div 2}{16 \div 2} = \frac{7}{8}\)[/tex].
- [tex]\(\frac{7}{8}\)[/tex] is exactly the same as the original fraction we have, so [tex]\(\frac{14}{16}\)[/tex] is indeed equivalent to [tex]\(\frac{7}{8}\)[/tex].
4. [tex]\(\frac{15}{18}\)[/tex]:
- Simplify [tex]\(\frac{15}{18}\)[/tex] by finding the GCD of the numerator and the denominator:
- The GCD of 15 and 18 is 3.
- Divide both the numerator and the denominator by 3: [tex]\(\frac{15 \div 3}{18 \div 3} = \frac{5}{6}\)[/tex].
- [tex]\(\frac{5}{6}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{15}{18}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
The fraction [tex]\(\frac{14}{16}\)[/tex] is equivalent to [tex]\(\frac{7}{8}\)[/tex].
Let's look at each fraction one by one:
1. [tex]\(\frac{14}{18}\)[/tex]:
- Simplify [tex]\(\frac{14}{18}\)[/tex] by finding the greatest common divisor (GCD) of the numerator and the denominator:
- The GCD of 14 and 18 is 2.
- Divide both the numerator and the denominator by 2: [tex]\(\frac{14 \div 2}{18 \div 2} = \frac{7}{9}\)[/tex].
- [tex]\(\frac{7}{9}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{14}{18}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
2. [tex]\(\frac{13}{15}\)[/tex]:
- The GCD of 13 and 15 is 1 (because 13 is a prime number and doesn't divide 15), so [tex]\(\frac{13}{15}\)[/tex] is already in its simplest form.
- [tex]\(\frac{13}{15}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{13}{15}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
3. [tex]\(\frac{14}{16}\)[/tex]:
- Simplify [tex]\(\frac{14}{16}\)[/tex] by finding the GCD of the numerator and the denominator:
- The GCD of 14 and 16 is 2.
- Divide both the numerator and the denominator by 2: [tex]\(\frac{14 \div 2}{16 \div 2} = \frac{7}{8}\)[/tex].
- [tex]\(\frac{7}{8}\)[/tex] is exactly the same as the original fraction we have, so [tex]\(\frac{14}{16}\)[/tex] is indeed equivalent to [tex]\(\frac{7}{8}\)[/tex].
4. [tex]\(\frac{15}{18}\)[/tex]:
- Simplify [tex]\(\frac{15}{18}\)[/tex] by finding the GCD of the numerator and the denominator:
- The GCD of 15 and 18 is 3.
- Divide both the numerator and the denominator by 3: [tex]\(\frac{15 \div 3}{18 \div 3} = \frac{5}{6}\)[/tex].
- [tex]\(\frac{5}{6}\)[/tex] is not the same as [tex]\(\frac{7}{8}\)[/tex], so [tex]\(\frac{15}{18}\)[/tex] is not equivalent to [tex]\(\frac{7}{8}\)[/tex].
The fraction [tex]\(\frac{14}{16}\)[/tex] is equivalent to [tex]\(\frac{7}{8}\)[/tex].
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