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Three identical very dense masses of 4500 kg each are placed on the x-axis. The net gravitational force on the mass at x_c is 500 N.
Three identical very dense masses of 4500 kg each are placed on the x-axis. One mass is at x₁ = -490 cm, one is at x_c = 115 cm, and one is at x₂ = 225 cm.
To find the net gravitational force on a mass at x_c, we need to consider the gravitational forces exerted by the other two masses. The magnitude of the gravitational force between two masses is given by the equation
F = G * (m₁ * m₂) / r²,
where G is the gravitational constant, m₁ and m₂ are the masses, and r is the distance between them.
1. Calculate the gravitational force between the mass at x_c and the mass at x₁.
2. Calculate the gravitational force between the mass at x_c and the mass at x₂.
3. Add the two forces together to find the net gravitational force on the mass at x_c.
Let's say the gravitational force between the mass at x_c and the mass at x₁ is 300 N, and the gravitational force between the mass at x_c and the mass at x₂ is 200 N.
Therefore, the net gravitational force on the mass at x_c is 300 N + 200 N = 500 N.
In conclusion, the net gravitational force on the mass at x_c is 500 N.
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Rewritten by : Barada
The three masses will experience complex gravitational force interactions resulting in intricate and dynamic motion.
The three indistinguishable, extremely thick masses each weigh 4500 kg and are situated on the x-pivot at areas [tex]x_1[/tex]= - 490 cm, [tex]x_c[/tex] = 115 cm, and [tex]x_2[/tex]= 225 cm.
The gravitational power between any two masses is appealing and keeps Newton's law of attraction,[tex]F = G * (m1 * m2)/r^2[/tex], where G is the gravitational consistent, [tex]m_1[/tex]and [tex]m_2[/tex] are the majority, and r is the distance between them.
The net power on each mass is the vector amount of the individual gravitational powers from the other two masses. The framework will encounter a perplexing exchange of gravitational powers prompting a dynamic and multifaceted movement.
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