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Answer :
The concentration of sodium (Na⁺) in the prepared intravenous solution is 9 meq/L.
To determine the concentration, we first need to look at the quantity of NaCl added to the solution.
Given data:
- NaCl added: 9 meq
- Volume of solution: 1 liter
We know that 1 meq of NaCl contains 1 meq of sodium ions (Na⁺) because sodium chloride (NaCl) dissociates completely in water to form Na⁺ and Cl⁻ ions in a 1:1 ratio.
Thus, the concentration of sodium ions in the solution is directly equal to the amount of NaCl added, which is:
Concentration of Na⁺ = amount of NaCl = 9 meq/L.
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