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If a ray of light shines in glass 1 with an index of refraction of 1.37 at an angle of 62°, into glass 2 with an index of refraction of 1.66, what is the angle of refraction in glass 2?

Answer :

By using Snell's Law and rearranging the equation, we can calculate the angle of refraction in glass 2 to be approximately 51.6 degrees.

In this case, we can use Snell's Law to determine the angle of refraction in glass 2. Snell's Law states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the indices of refraction of the two media:

n1 sin(θ1) = n2 sin(θ2)

Given that the index of refraction of glass 1 (n1) is 1.37 and the angle of incidence (θ1) is 62 degrees, and the index of refraction of glass 2 (n2) is 1.66, we can rearrange the equation to solve for the angle of refraction in glass 2:

n2 sin(θ2) = n1 sin(θ1)

sin(θ2) = (n1 sin(θ1))/n2

Plugging in the values into the equation, we can calculate:

sin(θ2) = (1.37 sin(62))/1.66

Using a calculator, we find that sin(θ2) ≈ 0.776

To find the angle of refraction in glass 2, we can take the inverse sine (sin^-1) of 0.776:

θ2 ≈ sin^-1(0.776)

Using a calculator, we find that θ2 ≈ 51.6 degrees.

Learn more about the topic of refraction here:

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